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100=-12x-3x^2
We move all terms to the left:
100-(-12x-3x^2)=0
We get rid of parentheses
3x^2+12x+100=0
a = 3; b = 12; c = +100;
Δ = b2-4ac
Δ = 122-4·3·100
Δ = -1056
Delta is less than zero, so there is no solution for the equation
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